3x - y = 5

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• \[ c^2 = 8^2 + 15^2 = 64 + 225 = 289 \]
• したがって、斜辺 \(c\) は：
• \[ c = \sqrt{289} = 17 \]
• まず、2番目の式から \(y\) を求めます：
• \[ 3x - y = 5 \implies y = 3x - 5 \]
• \(y = 3x - 5\) を1番目の式に代入します：

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