A rectangle has a perimeter of 50 cm. Its length is 5 cm more than twice its width. What is the area of the rectangle?
["A rectangle has a perimeter of 50 cm. Its length is 5 cm more than twice its width. What is the area of the rectangle?", "What’s the answer when a rectangle’s perimeter is exactly 50 centimeters—and its length stretches 5 centimeters more than twice its width? This question isn’t just a classroom geometry riddle—it’s a practical problem seen in design, building, and everyday planning across the U.S. With rising interest in efficient space use and smart design, understanding how to calculate dimensions and area can empower smarter choices, from furnishing a room to laying foundations. People are finding value in solving such problems data-backed and precise, especially as they seek answers backed by clear math rather than guesswork.", "### Why This Rectangle Problem Sparks Attention in 2024", "In a digital landscape where problem-solving and self-education drive content discovery, this rectangle challenge reflects a broader trend: curiosity about basic shapes influencing real-world decisions. From interior design to construction, knowing how perimeter and area connect helps users estimate materials, optimize space, and build confidence in planning. Social media platforms and educational apps highlight these types of challenges because they tap into immediate problem-solving satisfaction—user engagement stays high when answers feel accessible and applicable.", "Culturally, there’s growing public interest in STEM literacy, even at a foundational level. The clear, logical structure of this rectangle problem makes it ideal for mobile-first learners: straightforward, visual, and easy to follow. More than a simple equation, it represents how structured thinking transforms abstract geometry into tangible value—something users actively seek online, especially via platforms like Discover that reward depth and clarity.", "### How to Solve It: Step-by-Step", "Let’s break down how to find the area based on the rectangle’s perimeter and the relationship between length and width.", "Let the width be \( w \) centimeters. \nThen the length \( l \) is described as: \n\( l = 2w + 5 \)", "The formula for perimeter \( P \) of a rectangle is: \n\( P = 2 \ imes (length + width) \) \nSubstitute known values: \n\( 50 = 2 \ imes (l + w) \) \nReplace \( l \) with \( 2w + 5 \): \n\( 50 = 2 \ imes ((2w + 5) + w) \) \nSimplify inside the parentheses: \n\( 50 = 2 \ imes (3w + 5) \) \nDivide both sides by 2: \n\( 25 = 3w + 5 \) \nSubtract 5 from both sides: \n\( 20 = 3w \) \nSolve for \( w \):"]
