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Home / d_A^2 = (3 - 0)^2 + (2 - 0)^2 = 9 + 4 = 13

d_A^2 = (3 - 0)^2 + (2 - 0)^2 = 9 + 4 = 13

February 22, 2026

d_A^2 = (3 - 0)^2 + (2 - 0)^2 = 9 + 4 = 13

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G = \left( \frac{0 + 6 + 3}{3}, \frac{0 + 0 + 6}{3} \right) = (3, 2)
Now compute the squared distances from each vertex to $ G $:
From $ A = (0, 0) $:
From $ B = (6, 0) $:
d_B^2 = (3 - 6)^2 + (2 - 0)^2 = 9 + 4 = 13
From $ C = (3, 6) $:

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